Calculating aggs?

CYanchycki

Club Coordinator
So aggs are shown in MOA correct?

What is the conversion calculation to manually do it?

The average of your 5 targets say the average is .200" X 1.047"(actual moa) divided by 1?

Just wanting to know as I do not have a program to do the conversion unles someone is willing to share one?

Calvin
 
Groups are measured as to actual size in .000 inches. It's only the 200/300 yard groups that are corrected to MOA and then we divide by 2 for the 200 and by 3 for the 300. True MOA is not even an issue.
 
Thanks Mickey

So your are saying then at 200 yards if your average of the 5 groups in a agg is .600 you would divide by 2 to give you an oficial agg of .300?

It is simple math but I am missing something:confused::confused:

Calvin
 
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at 100 yards add the 5 groups together and double it, at 200 add the five groups and move the decimal over. Rick Hornbeck and Larry Engelbrecht taught me that one. I thank them both.
 
So your are saying then at 200 yards if your average of the 5 groups in a agg is .600 you would divide by 2 to give you an oficial agg of .300?

It is simple math but I am missing something:confused::confused:

Calvin
It's just that simple but the computer calculates that automatically. If all your 200 yard scores added together and divided by 5 to get an average the agg measurement is half that or, expressed in MOA.

Here are some of the groups shot at a prior match here at Rachel's Glen.
You can see that Jackie shot a .208, .348, .503,.655,.370 for a total of 2.084 inches but, as was mentioned, simply move the decimal one place to the left and it gives you MOA (2.084 divided by 5=.4168 divided by 2 to give MOA=.2084

1 JACKIE SCHMIDT 0.208 0.348 0.503 0.655 0.370 0.2084
2 WILBUR HARRIS 0.291 0.313 0.536 0.494 0.639 0.2273
3 BILLY STEVENS 0.279 0.454 0.493 0.656 0.547 0.2429
4 RICK McKAY 0.356 0.471 0.501 0.509 0.634 0.2471
5 KEN KORFF 0.515 0.568 0.438 0.365 0.602 0.2488
 
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Thanks Mickey

It's just that simple but the computer calculates that automatically. If all your 200 yard scores added together and divided by 5 to get an average the agg measurement is half that or, expressed in MOA.

Here are some of the groups shot at a prior match here at Rachel's Glen.
You can see that Jackie shot a .208, .348, .503,.655,.370 for a total of 2.084 inches but, as was mentioned, simply move the decimal one place to the left and it gives you MOA (2.084 divided by 5=.4168 divided by 2 to give MOA=.2084

1 JACKIE SCHMIDT 0.208 0.348 0.503 0.655 0.370 0.2084
2 WILBUR HARRIS 0.291 0.313 0.536 0.494 0.639 0.2273
3 BILLY STEVENS 0.279 0.454 0.493 0.656 0.547 0.2429
4 RICK McKAY 0.356 0.471 0.501 0.509 0.634 0.2471
5 KEN KORFF 0.515 0.568 0.438 0.365 0.602 0.2488
That is all I needed to see.

Calvin
 
At 100 add the five groups and divide by five then double them?
Never heard of that practice.

At 200 add the five groups and move the decimal over one place is right.
Actually he didn't say divide by five.
Match 1 .150, match 2 .150, match 3 .150 match 4 .150, match 5 .150.
His way
added up = .750 x 2 = 1.500 move the decimal 1 to the left = .150
or same thing .750 divided by 5 = .150
this is a simple example and it would be quite obvious that it was .150 agg. but try it with other numbers and it works every time. You could actually do any agg in your head and beat the guy with the calculator!
 
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just take

my agg and add .200 thou and that is about where you will always be


:') :.) smile


Jefferson
 
Resolving all to 100 yds...

Fifty yard aggs would be doubled. The formula is:

agg * (100 yds/agg distance yds)
 
To calculate an "aggregate" for 100 yd., average the group measurements to the fourth decimal place.
To calculate an aggregate for 200 yd., average the group measurements to four decimal places, and divide by 2. (For 300 divide by 3.)
To calculate a grand aggregate, average the yardage aggregates to four decimal places.
References to converting a 200 yd. aggregate to MOA by dividing the inch average by 2 may be common, but are a misuse of the term MOA. A Minute of Angle (or Minute of Arc) is one sixtieth fo a degree, which works out to approximately 1.047" at 100 yards, and twice that (2.094) at 200.
 
Francis

Doubling the 100 yd agg and moving the decimal one place left is the same as dividing by 5, just faster 2*Total/(2*5)=Agg
 
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